Problema Solution
the difference between two positive integers is 6. If the smaller is added tot he square of the larger, the sum is 336.
Answer provided by our tutors
Let 'x' and 'y' represent the two positive integers and let x > y (y is the smaller).
x - y = 6
y + x^2 = 336
y = 336 - x^2
Plug y = 336 - x^2 into x - y = 6:
x - 336 + x^2 = 6
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click here to see the equation solved for x
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x = 18
18 - y = 6
y = 18 - 6
y = 12
The two numbers are 18 and 12.