Problema Solution
the height in feet of a diver above the surface of a pool is given by the equation h(t)=-16t^2+12t+8, where t is the time in seconds after the diver jumps. How many seconds after jumping is the divers height 5 meters? How long does it take the diver to reach the water
Answer provided by our tutors
h(t)=-16t^2+12t+8
We need to find t such that h(t) = 5.
In other words, we need to solve the following equation:
-16t^2+12t+8 = 5
........
click here to see the equation solved for t
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t = 0.95 s
We need to ignore the negative solution since the time can only be positive.
After 0.95 seconds the diver's height is 5 meters.
The diver will reach the water when h(t) = 0 that is:
-16t^2+12t+8 = 0
........
click here to see the equation solved for t
........
t = 1.18 s
We need to ignore the negative solution since the time can only be positive.
After 1.18 seconds the diver will reach the water.