Problema Solution
The height in feet reached by a ball seconds after being thrown vertically upward at 320ft/s is given by s=320t-16t^2. Find the greatest height reached by the ball and the velocity with which it reaches the ground.
Answer provided by our tutors
s=320t-16t^2
We need to find s max for the parabolic function s=320t-16t^2
s max = c - b^2/(4a), where a = -16, b = 320, c = 0
s max = 0 - 320^2/(4*(-16))
s max = 5 ft
The greatest height reached by the ball is 5 feet.