Problema Solution
The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2+104t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.
Answer provided by our tutors
The height of the object h, depending on the time t, is given by the formula:
h(t) = -16t^2+104t
The point of departure is the start moment when t = 0 s, and the height at that moment is h(0) = 0 ft.
The object returns to its point of departure after t seconds when the height becomes 0 that is h(t) = 0 thus we have:
-16t^2+104t = 0
Click here to see the solution of the quadratic equation
t = 6.5 s
The object will hit return to its point of departure (hit the ground) in 6.5 seconds.