Problema Solution
The hydraulic oil reservoir of a tractor is 30 inches long, 14 inches wide, and 2 1/2 feet deep. how many gallons of oil are required to fill the reservoir to 7/8 of its depth?
Answer provided by our tutors
The volume of the reservoirs in in^3 is:
V = 30*14*(3/2)*12* (since 1 ft = 12 in)
1 gal = 231 in^3
((7/8)V) : 231 = ((7/8)30*14*(3/2)*12)/231 = 28.64 gal
28.64 gallons of oil are required to fill the reservoir to 7/8 of its depth.