Problema Solution
The length of a rectangle is
3 yds more than double the width, and the area of the rectangle is
77 yd. Find the dimensions of the rectangle
Answer provided by our tutors
Let
w = the width of the rectangle, w>=0
l = the length of the rectangle
A = 77 yd^2 the area of the rectangle
The length is 3 yd more than twice the width:
l = 3 + 2w
The area of rectangle equals the product of its width and length:
A = w*l
Plug l = 3 + 2w and A = 77 into the above equation:
w(3 + 2w) = 77
........
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........
w = 5.5 yd
We need to ignore the negative solution -7 since the width is always positive.
l = 3 + 2*5.5
l = 14 yd
The dimensions of the rectangle are 5.5 yards and 14 yards.