Problema Solution
The length of a rectangle is 4yd longer than its width.If the perimeter of the rectangle is 28yd, find its area.
Answer provided by our tutors
Let
w = the width
l = the length
P = 28 yd the perimeter
l = w + 4
The perimeter is P = 2l + 2w thats why we have:
2l + 2w = 28 divide both sides by 2
l + w = 14
We have the following system of equations:
l = w + 4
l + w = 14
........
click here to see the system of equations solved for l and w
........
l = 9 yd
w = 5 yd
The area A = l*w
A = 9*5
A = 45 yd^2
The area of the rectangle is 45 yd^2.