Problema Solution
the length of a rectangular park measures two yards shorter than double the width of this park. the area of the park measures 180 yards please determine the width of this park, length of the park and perimeter of this park
Answer provided by our tutors
Let
x = the width of the park, x>=0
2x - 2 = the length of the park
A = 180 yd^2 the area of the park
P = the perimeter of the park
Since A = width*length we have:
x(2x - 2) = 180
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click here to see the equation solved for x
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x = 10 yd
2*10 - 2 = 18 yd
The width is 10 yards while the length is 18 yards.
P = 2*width + 2*length
P = 2*10 + 2*18
P = 56 yd
The perimeter of the park is 56 yards.