Problema Solution
The length of the base of a rectangular solid is 12 dm and the width is 5 dm. What should the height of the rectangular solid be so that its volume is smaller than the volume of a cube with a side of 9 dm?
Answer provided by our tutors
l = 12 dm
w = 5 dm
h = ?
The volume of the rectangular solid is: V1 = l*w*h
V1 = 12*5*h
V1 = 60h dm^3
The volume of the cuber with side a = 9 dm is: V2 = a^3
V2 = 9^3
V2 = 729 dm^3
V1 < V2
60h < 729
........
click here to see the inequality solved for h
........
h < 12.15
The height of the rectangle should be smaller than 12.15 dm.