Problema Solution
The perimeter of a rectangle is 300 ft and the length of the rectangle is 3 ft more than twice the width. Find the dimensions of the rectangle
Answer provided by our tutors
Let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
The length of the rectangle is 3 ft more than twice the width:
l = 3 + 2w
The perimeter is 300 ft:
P = 300 ft
P = 2l + 2w
2l + 2w = 300
plug l = 3 + 2w into the last equation:
2(3 + 2w) + 2w = 300
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click here to see the step by step solution for w
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w = 49 ft
l = 3 + 2*49
l = 101 ft
The dimensions of the rectangle are: the length is 101 ft and the width is 49 ft.