Problema Solution
The perimeter of the base of a regular quadrilateral prism is 32 cm. The height of the prism is 2 times greater than the length of the base edge. Find the sum of all edges of the prism.
Answer provided by our tutors
Let
a = the base edge (the base is square)
h = 2a the height of the prism
The perimeter of the base is:
4a = 32 divide both sides by 4
a = 32/4
a = 8 in
h = 2*8
h = 16 in
The sum of all edges is:
8a + 4h = 8*8 + 4*16 = 64 + 64 = 128 in
The sum of all edges if the prism is 128 inches.