Problema Solution
the speed of a moving sidewalk at an airport is 3ft/sec. A person can walk 87 ft forward on the moving sidewalk in the same time it takes to walk 12 ft on a nonmoving sidewalk in the opposite direction. At what rate would a person walk on a nonmoving sidewalk?
Answer provided by our tutors
Let
v = 3 ft/sec the speed of the moving sidewalk
v1 = the rate of the person
t = the time of the walk in each direction
Walking forward on the moving sidewalk the rate of the movement is: v + v1 = 3 + v1
Walking on non moving sidewalk in opposite direction the rate of the movement is: v1
Since distance = speed*time we have:
(v + v1)*t = 87
(3 + v1)*t = 87
Walking on non moving sidewalk in opposite direction the rate of the movement is v1:
v1*t = 12 divide both sides by v1
t = 12/v1
Plug t=12/v1 into (3 + v1)*t = 87 we get:
(3 + v1)*(12/v1) = 87
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click here to see the equation solved for v1
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v1 = 0.48 ft/s
The rate of the person on a non-moving sidewalk is 48 feet per second.