Problema Solution

The sum of three consecutive integers is 21 larger than twice the smallest integer. Find the integer.

Answer provided by our tutors

The three consecutive integers can be written as:

x-1, x and x+1, where x is integer.

x - 1 is the smallest integer of the the three.

The sum of three consecutive integers is 21 larger than twice the smallest integer:

(x - 1) + x + (x + 1) = 21 + 2(x - 1)

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click here to see the equation solved for x

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x = 19

x - 1 = 19 - 1 = 18

19 + 1 = 20

The three integers are 18, 19 and 20.