Problema Solution
The time a basketball player spends in the air when shooting a basket is called the "hang time." The vertical leap L measured in feet is related to the hang time t measured in seconds by the equation Lequals
4 t squared.
Suppose that a basketball player has a vertical leap of 2
feet 4
inches. Find the hang time for this leap.
The hang time for a vertical leap of 2
feet 4
inches is seconds.
Answer provided by our tutors
L = 4t^2
1 ft = 12 in
1 in = 1/12 ft
4 in = 4/12 ft = 1/3 ft
2 ft 4 in = 2 1/3 ft = 7/3 ft
We need to solve for t:
4t^2 = 7/3
........
click here to see the equation solved for t
........
t = 0.76 s
The hang time for a vertical leap of 2 feet 4 inches is 0.76 seconds.