Problema Solution
The volume V of given mass of gas varies directly as the temperature T and inversely as the pressure P. If V= 230.0 in.3 when T = 230 and P = 15 lb/in in.2, what is the volume when T = 160 and P = 10/in.2?
Answer provided by our tutors
V = C*T/P, where C is constant
VP/T = C
V1 = 230.0 in^3
T1 = 230
P1 = 15 lb/in^2
We need to find V2 when T2 = 160 and P2 = 10 lb/in^2.
V2P2/T2 = V1P1/T1
V2*10/160 = 230*15/230
click here to see the equation solved for V2
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V2 = 240 in^2
When T = 160 and P = 10lb/in^2 the volume is V = 240 in^3.