Problema Solution
the width of a rectangle is 13 ft less than twice its length, if the area of the rectangle is 68 sq ft , find its length and width
Answer provided by our tutors
Let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
The width of a rectangle is 13 ft less than twice its length:
w = 2l - 13
The area is 68 ft^2:
l*w = 68
plug w = 2l - 13 into the last equation:
l*(2l - 13) = 68
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click here to see the equation solved for l
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l = 9.93 ft
w = 2*9.93 - 13
w = 6.86 ft
The length is 9.93 ft and the width is 6.86 ft.