Problema Solution
Two cars are 468 mi apart and traveling toward each other along the same road. They meet in 3 hr. One car is traveling 8mph slower than the other. What is the speed of each car?
Answer provided by our tutors
Let
v = the speed of the slower car
v + 8 = the speed of the faster car
t = 3 hr the time of the travel
d = 468 mi the sum of the distances that each car travels
Since distance = speed*time we have:
vt + (v + 9)t = d
3v + 3(v + 8) = 468
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click here to see the equation solved for v
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v = 74 mph
74 + 8 = 82 mph
The speed of the slower car is 74 mph, while the speed of the faster car is 84 mph.