Problema Solution
Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (-4,-6) and parallel to the line whose equation is y=-3x+4
Answer provided by our tutors
The slope of the line y=-3x + 4 is m = -3.
Substitute the slope from original line (-3 in this case) into the slope-intercept equation of the line y = mx + b:
y = (-3)x + b
Plug the values x = -4 and y = -6 (since the line goes through (-4, -6)) to find b:
-6 = (-3)(-4) + b
b + 12 = -6
b = - 6 - 12
b = -18
The slope-intercept equation of the line is y = -3x - 18.
The point-slope equation of the line is:
y − y1 = m(x − x1), where m = -3, x1 = -4, y=-6
We plug the values into the equation and get the point-slope equation of the line:
y − (-6) = (-3)(x − (-4))