Problema Solution
We have a 40% acid solution and we want 75 liters of a 15% acid solution. How much water should we put into the 40% solution to do this?
Answer provided by our tutors
Let x represent the ml of water (0% acid solution).
0.40*(75 - x) + 0*x = 0.15*75
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x = 46.875 ml
We should add 46.875 ml of water.