Problema Solution
We want to select a committee of five members from a group of four women and six men. The order of selection is irrelevant.
What is the total number of committees we can make?
Answer provided by our tutors
Since the order is irrelevant we need to find the number of 5-comibnations of a set of 4 + 6 = 10 elements:
C(10, 5) = 10!/(5!(10-5)!)
C(10, 5) = (6*7*8*9*10)/(2*3*4*5)
C(10, 5) = 252
The total number of committees is 252.