Let the width be 'x' then the length is '32/x' (since the area equals width multiplied by length).

The perimeter is calcualted by the formula:

P = 2*width+2*length

P = 2x + 2y

P = 2x + 2*32/x

P = 2x + 64/x

We will find minimum by finding the first derivative:

P' = 2 - 64/x^2

P' = 0 for a min of P

So we have:

2 - 64/x^2 = 0

64/x^2 = 2

x^2 = 32

x= √32

32/x = 32/√32 = √32

The least perimeters is:

P = 2*√32 + 2*√32

P = 4*√32

P = 22.63