Problema Solution
You drive from Fayetteville to Winston-Salem, by way of Sanford. When you leave Fayetteville it is 11:00 AM. In Sanford, you stop for a 30-minute lunch, then you drive the rest of the way to your destination, which is twice the distance you drove from Fayetteville to Sanford. You drive at an average speed of 50 mph for the trip from Fayetteville to Sanford, and you drive an average of 60 mph from Sanford to Winston-Salem. If you arrive in Winston-Salem at 1:43 PM, what is the total distance you drove?
Answer provided by our tutors
Let
x = the distance from Fayetteville to Sanford
2x = the distance from Stanford to Winston-Salem
The total time of the travel without the 30 min lunch is: 1:43 PM - 11 AM - 30 min = 2 h 43 min - 30 min = 2 h 13 min = 2 + 13/60 hours.
v1 = 50 mph the average speed from Fayetteville to Sanford
v2 = 60 mph the average speed from Sanford to Winston-Salem
Since speed = distance/time follows time = distance/speed
x/v1 + 2x/v2 = 2 + 13/60
x/50 + 2x/60 = 2 + 13/60
........
click here to see all the equation solution steps
........
x = 41.56 mi
The total distance is x + 2x = 3x = 3*41.56 = 124.68 miles.