Problema Solution
A Ball Is thrown from a height of 79 meters with an initial downward velocity of 6m/s. The ball's height h (in meters) after T Seconds is given by the following
H=79-6t-5t^2
How long after the ball is thrown does it hit the ground?
Round answer(s) to the nearest hundredth.
Answer provided by our tutors
The ball hits the ground after t seconds when H(t) = 0 that is when:
79 - 6t - 5t^2 = 0
........
click here to see the equation solved for t
........
t = 3.42 sec approximately
We need to ignore the negative solution -4.62 since the time can not be negative.
The ball will hit the ground after 3.42 seconds approximately.