Problema Solution
A ball is tossed upwards from a height of 200 feet with an initial velocity of 45 feet/second. The height h(1) of the ball above the ground t seconds after being tossed is given by the function shown below.
h(t)= -16t^2+45t + 200
Determine the time in seconds after being tossed that the ball reaches a height of 100 feet above the ground.
Answer provided by our tutors
h(t)= -16t^2+45t + 200
We need to find t such that h(t) = 100 ft, that is, solve the following quadratic equation:
-16t^2+45t + 200 = 100
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click here to see the step by step solution of the quadratic equation for t
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t = 4.27 s
We need to ignore the negative solution since the time can not be negative.
4.27 seconds after the ball is tossed it will reach height of 100 feet above the ground.