Problema Solution
A certain chain saw requires a fuel mixture of 5.5% oil and the remainder gasoline. How many liters of 2.5% mixture and how many of 9% mixture must be combined to produce 40.0 liters of 5.5% mixture?
Answer provided by our tutors
Let
x = liters of 2.5% mixture
y = liters of 9% mixture
We have the following system of equations:
x + y = 40
0.025x + 0.09y = 0.055*40
........
click here to see the system of equations solved for x and y
........
x = 21.54 L
y = 18.46 L
21.54 liters of 2.5% mixture must be combined with 18.46 liters of 9% mixture to produce 40.0 liters of 5.5% mixture.