Problema Solution
A rancher wants to use 300 feet of fencing to enclose a rectangular area of 4400 square feet. What dimensions should the rectangle have?
Answer provided by our tutors
Let 'x' and 'y' represent the dimensions of the rectangle.
The perimeter of the rectangle is 300 ft:
2(x + y) = 300 divide both sides by 20
x + y = 150
y = 150 - x
The area of the rectangle is 4400 ft^2:
x*y = 4400
Plug y = 150 - x into x*y = 4400:
x(150 - x) = 4400
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click here to see the equation solved for x
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x1 = 110 ft
x2 = 40 ft
For x = 110 ft we have y = 150 - 110 = 40 ft.
For x = 40 ft we have y = 150 - 40 = 110 ft.
The dimensions of the rectangle are: 110 ft and 40 ft.