Problema Solution
A passenger train left Washington and traveled at an average speed of 15 mph. A cattle train left six hours later and traveled in the same direction but with an average speed of 24 mph. Find the number of hours the passenger train traveled before the cattle train caught up.
Answer provided by our tutors
Let
v1 = 15 mph the average speed of the passenger train
v2 = 24 mph the average seed of the cattle train
t = the time that the passenger train traveled
Let
v1 = 15 mph the average speed of the passenger train
v2 = 24 mph the average seed of the cattle train
t = the time that the passenger train traveled
t - 6 = the time that the cattle train traveled (6 hours later means that it traveled 6 hours less)
Since distance = speed*time we can write:
v1*t = v2(t - 6)
15t = 24(t - 6)
........
........
t = 16 hr
The passanger train traveled 16 hours before the cattle train caught up.