Problema Solution
Carroll bikes 1 kilometer east,4 kilometers north, and then 5 kilometers east again. How far is Carroll from her starting position?
Answer provided by our tutors
Let 'd' represent Carroll's distance from her starting position.
Using the Pythagorean Theorem we have:
d^2 = 4^2 + (1 + 5)^2
d^2 = 16 + 36
d^2 = 52
d = 7.21 km
Carroll is 7.21 km from her starting position.