Problema Solution
Find a function to represent the set of all points equidistant from the point (-2, 3) and the line y=7.
Answer provided by our tutors
The distance from a point (m, n) to the line Ax + By + C = 0 is given by:

If the line is y = 7, that is, y - 7 = 0 the distance is:
d = |1*n - 7|/√1^2
d^2 = (n - 7)^2
The distance from (m, n) to (-2, 3) is:
d^2 = (m+2)^2 + (n-3)^2
Now we have
(n - 7)^2 = (m+2)^2 + (n-3)^2
by simplifying the above expression we get:
-8n - m^2 - 4m + 36 = 0
Since (m, n) is any point from the line, instead of m we can put x, and instead of n we can put y and get:
-8y - x^2 - 4x + 36 = 0
y = -(1/8)(x + 2)^2 + 5
The function to represent the set of all points equidistant from the point (-2, 3) and the line y=7 is the parabola:
y = -(1/8)(x + 2)^2 + 5