Problema Solution
Two medical representatives leave a hotel at the same time but travel by car in opposite directions. Rolly's average speed is 3 kph faster than Juancho's. Find their rates of speed if after 5 hours, they are 455 kilometres apart.
Answer provided by our tutors
Let
v = Juancho's rate
v + 3 = Rolly's rate
t = 5 hr the time of the travel
d = 455 km the distance between the cars after 5 houra
Since distance = speed*time and the cars travel in opposite direction we have:
vt + (v + 3)t = d
5v + 5(v + 3) = 455
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click here to see the equation solved for v
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v = 44 kph
v + 3 = 44 + 3 = 47 kph
Juancho's rate was 44 kph while Rolly's rate was 47 kph.