Problema Solution
If an Object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any given time t is given by:
H=-16t^2+vt+s
Solve for t when the object hits the ground. (when h=0)
t=blank1 ± square root of blank2 -4(blank 3) over 2(-16)
Fill in the blanks using the quadratic formula
Answer provided by our tutors
We need to solve the quadratic equation:
-16t^2+vt+s = 0, where a = -16, b = v, c = s
t = (-v ± square root of (v^2 - 4(-16)s)/(2*(-16))
t = (-v ± square root of (v^2 + 64s)/(-32)
blank1 = -v
blank2 = v^2
blank3 = -16s
t=-v ± square root of v^2 -4(16s) over 2(-16)