Problema Solution
Quadratic relation has zeros -3 and 7 and y-intercept of 8. Determine equation of quadratic in factored form
Answer provided by our tutors
The quadratic equation with zeros -3 and 7 can b written as:
y = a(x - (-3))(x - 7), where 'a' is the quotient we need to find
The y-intercept is 8 we have:
a(0 - (-3))(0 - 7) = 8
-21a = 8
a = -8/21
The quadratic equation in factored form is:
y = (-8/21)(x - (-3))(x - 7)
The quadratic equation in expanded form is:
y = (-8/21)x^2 - (32/21)x + 8