the flight of a golf shot reached a maximum height of 22.5 yards and the golf ball landed 300 yards from th point of impact assume the point of impact is (0,0).Write a quadratic function =a (x-p)(x-q) that represents the flight of the ball.

Answer:

Solving for a vertical quadratic equation passing through these three points:

(0,0), (150, 22.5) and (300, 0)

gives these equations:

0=a*0^2 + b*0 + c

22.5 = a*150^2 + b*150 + c

0 = a*300^2 + b*300 + c

leads to:

c=0

a=-1/1000

b=3/10

the quadratic equation:

y=(-1/1000)*x^2 + (3/10)*x + 0

f(x) = (-1/1000)(x-150)(x-150) + 45/2

where a=-1/1000, p=150, q=150 in the form requested