Problema Solution
The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 14.6 degrees. If skyscraper B is 1431 feet tall, how far apart are the skyscrapers? Assume the bases of both buildings are at the same elevation.
Answer provided by our tutors
calculation:
we draw triangle and see it 90°. As we know height of building B and inclination angle we can get the lenght of base of the triangle.
L- distance
tan14,6=1431/L
L=1431/tan14.6 = 5493.69ft
:)