Problema Solution
Find two integers that differ by 6 while their squares differ by 132.
Answer provided by our tutors
a) x-y=6
b) x^2 - y^2 = 132
From a) x=6+y, then in b) (6+y)^2+y^2=132, 36+12y+y^2-y^2=132, 12y=132-36, 12Y=96, y=8, and then, x=6+y, x=6+8, x= 14