Problema Solution
A backpacker hiking into a wilderness area walked 16 mi at a constant rate and then reduced this rate by 1 mph. Another 9 mi was hiked at this reduced rate. The time required to hike the 9 mi was 1 h less than the time required to walk the 16 mi. Find the rate at which the hiker walked the first 16 mi.
Answer provided by our tutors
Solution: the total mi he walks is 16 + 9, the time used for 16mi is X, the rate of 16mi is Y
So Y X =16, (Y-1) (X-1)=9
Y = 4, X = 4
The rate for 16mi is 4