Problema Solution
Five years ago the age of a father was twice the age of his son. The sum of their present ages is 55 years. Find their present ages.
Answer provided by our tutors
sol.
let the present ages of father be F and son be S.
according to question
F-5 = 2(S-5)
=> F = 2S -5-----------(1)
also,
F+S =55
=> 3S =60
=> S = 20years and F = 35 years