Problema Solution
The perimeter of a rectangle is 42m , and the area of the rectangle is 90m^2 . Find the dimensions of the rectangle
Answer provided by our tutors
Let length of rectangle=l meter and width of rectangle=w meter.
So, 2(l+w)=42
l+w=21---equation-1
And lw=90- ---equation-2
Plugging l=21-w in second equation.
(21-w)w=90
21w-w^2=90
w^2-21w+90=0
(w-15)(w-6)=0
w=15 and 6
Dimension is width=15 or 6 and length=6 or 15.