Problema Solution
A basketball team sells $10,$20, and $30 tickets. They sold 186 more $20 tickets than $10 tickets and total amount of tickets sold was 474. How many of each tickets were sold. The total revenue from the tickets was $8,640
Answer provided by our tutors
Let number of $10 ticket sold=x, so number of $20 ticket sold=x+186.
Let number of $30 ticket sold=y.
So, x+x+186+y=474
2x+y=288.
Therefore y=288-2x
10x+20(x+186)+30y=8640
10x+20x+3720+30y=8640
30x+30y=8640-3720
30(x+y)=4920
x+y=4920/30=164
After plugging y=288-2x
x+288-2x=164
-x=164-288
x=124
So, Number of $10 ticket sold=124
Number of $20 ticket sold=310
Number of $30 ticket sold=40