Problema Solution
The acute triangle ABC is inscribed in a circle of radius 3. If BC = 2,
compute sin BAC.
Answer provided by our tutors
The acute triangle ABC is inscribed in a circle of radius 3. If BC = 2,
compute sin BAC.
Solution:
BC/sinBAC = 2r
sin BAC = BC/2r = 2/(3*2)=1/3
So sin BAC = 1/3