Problema Solution
How many gallons of a 10% salt solution must be mixed with 40 gallons of a 30% solution to obtain a 20% solution?
Answer provided by our tutors
We can write this as:
.1(x-40)+.3(40)=.2x
Where 'x-40', '40' and 'x' are the amounts of .1, .3, and .2 solutions.
Using Algebrator to solve for x, we get:
x=80
therefore the amount of 10% needed is x-40=80-40=40 gallons