Problema Solution
If Neil weighng 150 pounds jumps w/an initial velocity of 8ft/sec, calculate his hang time on the earth aswell as his hang time on the moon, given that the moon has 1/6th the gravitational pull of the earth. Then calculate the max height of his jump in each location
Answer provided by our tutors
we use the following formula to calculate height, 'h', under the effect of gravity:
h = vt - (1/2)gt^2, where g = 9.8m/s^2 and 't' represents time in seconds
8 ft/s * 0.3048 = 2.4384 m/s
we treat mass as inconsequential to the problem, considering only the effect of initial velocity and gravitational pull
to find his 'hang time' we solve for h=0, knowing that t=0 will be the first value (before the jump):
0 = 8(0.3048)t - (9.8/2)t^2
solving for 't' we have t=0.497
the 'hang time' will be approximately 0.5 seconds, or 1/2 of a second
the maximum height will be 0.2488m, or 0.816 feet, or 9.8 inches
on the moon, the hang time and height will increase by a factor of 6
hang time: approximately 3 seconds on the moon
maximum height: approximately 2.4 feet