Problema Solution
A jet plane, flying 110 mph faster than a propeller plane, travels 6930 miles in 4 hours less time than the propeller plane takes to fly the same distance. How fast does each plane fly?
Answer provided by our tutors
Using the general equation d=rt (distance=rate*time), we can write:
Jet plane:
6930=(r+110)(t-4)
propeller plane:
6930=rt
where 'r' is the rate of the propeller plane and 'r+110' is the rate of the jet plane. Using Algebrator to solve for r, we get:
r=385 mph (rate of the propeller plane)
Therefore:
r+110= 495 mph (rate of the jet plane)