Problema Solution

A University bookstore recently sold a wirebound graph-paper notebook for $0.76 and a college-ruled notebook for $3.68. A combination of 50 of these notebooks were sold for a total of $128.52. How may of each type were sold?

Anna

Answer provided by our tutors

Lets make wirebound = x

Lets make college rule = y


x + y = 50 [an undefined amount of wirebound and college ruled notebook is 50 notebooks]


.76x + 3.68y = 128.52 [ $.76 per wirebound and $3.68 per college ruled came out to be $128.52]


Lets solve the first equation for x.


x + y = 50 --> x = 50 - y [Subtract y from both sides]


Plug that equation into the variable for x into the second equation.


.76x + 3.68y = 128.52 --> .76(50 - y) + 3.68y = 128.52


38 - .76y + 3.68y = 128.52

2.92y = 90.52 [Simplify the y terms, and subtract 38 from both sides]

y = 31 [Divide both sides by 2.91]


Now we know y is 31, we plug that back into the first equation to get,


x + y = 50

x + 31 = 50

x = 19 [Subtract both sides by 31]


The university bookstore sold 19 wirebound graph-paper notebooks and 31 college-ruled notebooks.


You may check your work by plugging the values of x and y back into the two equations, and it should come out right.

 

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