Problema Solution
$6300 is invested, part of it at 12% and part of it at 6%. For a certain year, the total yield is $564.00. How much was invested at each year.
another one is:
A baseball team has home games on Wed. and Sat. The two games together earn $5117.50 for the team. Wed game generates $357.50 less than Sat game . How much money was taken in at each game.
Thank you
Answer provided by our tutors
please submit word problems one-at-a-time, here we answer the first question only
let 'x' represent the amount invested at 12%, then '6300-x' represents the amount invested at 6%
interest = principal * rate * time
we assume time to be equal to 1
564 = 0.12x + 0.06(6300-x)
solving for 'x' we have x=3100
6300-3100 = 3200
$3,100 was invested at 12%, $3,200 was invested at 6%