Problema Solution
the length of a rectangle exceeds it width by 4 feet. If its area is 32 square feet find its dimension
Answer provided by our tutors
let 'w' represent the width of the rectangle in feet, then 'w+4' represents the length
area = length * width
32 = w(w+4)
solving for 'w' we have a positive value of w=4
4+4=8
the width of the rectangle is 4 ft, its length is 8 ft