Problema Solution
josh and nigel live 13 miles apart. they meet at ihop that lies between their homes. josh jogs 10 mph, nigel 8 mph. josh is faster, so he leaves 30 minutes later. how long will it take joshua?
Answer provided by our tutors
Let 't1' be the time Josh needs and 't2' the time Nigel needs to get to ihop. We need to find t1.
Since the ihop lies between their homes each of them will pass same distance:
10 * t1 = 8 * t2
Josh is faster and needs 30 min = 30/60 hours = 0.5 hours less than Nigel to get to the ihop:
t1 = t2 - 0.5
If we substitute for t1 in the first equation we get
10 * (t2 - 0.5) = 8 * t2
10 * t2 - 10 * 0.5 = 8 * t2
10 * t2 - 5 = 8 * t2
10 * t2 - 8 * t2 = 5
2 * t2 = 5
t2 = 5 / 2
t2 = 2.5 hours
t1 = t2 - 0.5 = 2.5 - 0.5 = 2 hours
Josh needs 2 hours to get to the ihop.