Problema Solution
Victor has ₱16.25 in coins. If there were twice as many 5-centavo coins as 25 centavo coins, and as many 10 centavo coins as 5 centavo coins and 25 centavo coins combined, how many coins of each type were there?
Answer provided by our tutors
let 'x' represents the number of 25-centavo coins, then '2x' represents the number of 5-centavo coins and '2x+x' represents the number of 10-centavo coins
16.25 = 0.25x + 0.05(2x) + 0.10(2x+x)
solving for 'x' we have x=25
2*25 = 50
50 + 25 = 75
there were 25 25-centavo coins, 75 10-centavo coins and 50 5-centavo coins