Problema Solution
how much pure acid should be mixed with 5 gallons of a 50% acid solution in order to get an 80% acid solution?
Answer provided by our tutors
Let 'x 'represent the amount of pure acid added we have
50% of 5 + 100% of x = 80% total gallons of both
0.50*5 + 1* x = 0.80*(5+x)
Simplify and Solve
0.50*5 + 1* x = 0.80*(5+x)
0.2*x = 0.80*5 - 0.50*5
0.2*x = 0.3*5
0.2*x = 1.5
x = 15/2 = 7.5 gal
Indeed
05*5 + 7.5 = 10 = 0.8* 12.5
We need 7,5 gal pure acid.