March 1: a1 = $10 winnings

March 2: a2 = $25 winnings

March 3: a3 = $1000 winnings

If the winnings a1, a2, a3, ....,a15, we need to find a15.

I dont seem to recognize any pattern.

a1: 10 prime factors to 2*5

a2: 25 prime factors to 5*5

a3: 100 prime factors to 2*2*5*5

if we pretend that a0 is 1*1 = 2^0 * 5^0 then we can guess at a pattern like 2^n * 5^n for odd sequences and 5^p for even ones

so for ax when x is even, we have n = x and for ax when x is odd, we have n=(x-1)

for a15, x is odd, hence a15 must equal 2^15 * 5^15 = 1 * 10^12